Get Web Service Content

Question

I have a url like here . When I enter it into the Safari address bar, I see a result, such as "Error" or "OK."

So, how to properly call this URL from my code and get this result as a string?

I tried it with NSURLConnection, NSURLRequestand NSURLResponse, but my answer object is always nil.

Answer 1

The "response" in these classes refers to the protocol response (HTTP headers, etc.), and not to the content.

To get content, you have several options:

• NSURLConnection : NSURLConnection

• NSURLConnection :

  // Error checks omitted
  NSURL *URL = [NSURL URLwithString:@"http://www.myserver.com/myservice.php?param=foobar"];
  NSURLRequest *request = [NSURLRequest requestWithURL:URL];
  NSData *data = [NSURLConnection sendSynchronousRequest:request
                                       returningResponse:nil
                                                   error:nil];
  

• [NSString stringWithContentsOfURL:]

  NSURL *URL = [NSURL URLwithString:@"http://www.myserver.com/myservice.php?param=foobar"];
  NSString *content = [NSString stringWithContentsOfURL:URL];
  

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