Free ctypes open library in Python

Question

I was wondering if I would open my dll library compiled from user c code like this:

import ctypes
my_lib = ctypes.cdll.LoadLibrary('./my_dll.dll')
my_func = my_lib.my_func
# Stuff I want to do with func()

I need to close my_lib object after use, how is the file? Will this make the code cleaner, more efficient and more "pythonic"?

Thanks!

Answer 1

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POSIX

#include <stdio.h>

void __attribute__((constructor)) initialize()
{
    printf("initialize\n");
}

void __attribute__((destructor)) finalize()
{
    printf("finalize\n");
}

POSIX Python

>>> import ctypes
>>> lib1 = ctypes.CDLL('./lib.so')
initialize
>>> lib2 = ctypes.CDLL('./lib.so')
>>> lib1._handle == lib2._handle
True

>>> import _ctypes
>>> _ctypes.dlclose(lib1._handle)
>>> _ctypes.dlclose(lib1._handle)
finalize

>>> lib1 = ctypes.CDLL('./lib.so')
initialize
>>> _ctypes.dlclose(lib1._handle)
finalize

Windows

#include <stdio.h>
#include <windows.h>

void initialize()
{
    printf("initialize\n");
}

void finalize()
{
    printf("finalize\n");
}

BOOL WINAPI DllMain(HINSTANCE hinstDLL,
                    DWORD fdwReason,
                    LPVOID lpReserved)
{
    switch(fdwReason) 
    { 
        case DLL_PROCESS_ATTACH:
            initialize();
            break;

        case DLL_PROCESS_DETACH:
            finalize();
    }
    return TRUE;
}

Windows Python

>>> import ctypes
>>> lib1 = ctypes.CDLL('./lib.dll')
initialize
>>> lib2 = ctypes.CDLL('./lib.dll')
>>> lib1._handle == lib2._handle
True

>>> import _ctypes
>>> _ctypes.FreeLibrary(lib1._handle)
>>> _ctypes.FreeLibrary(lib1._handle)
finalize

>>> lib1 = ctypes.CDLL('./lib.dll')  
initialize
>>> _ctypes.FreeLibrary(lib1._handle)
finalize