Get the length of the array that contains element 0 when going to the function

Question

Is there a way to print the length of an array that contains element 0, and this array was passed to a function that can only have one argument as an array?

Example:

int arrLen(int arr[])
{
    //get size here;
}

int main()
{
    int arr[]={0,1,2,3,4,5};
    arrLen(arr);
}

In C ++, there is a restriction that we cannot compare array elements with NULL if it has zero, but still asks if there is a way to do this. I can only pass an array of functions - this is my limitation.

Answer 1

In your example, you can use a function template to get what you want:

template <size_t N>
int arrLen(int (&arr)[N])
{
    return N;
}

Answer 2

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Answer 3

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:

int arr[] = {-1,0,1,2,3,4,5};
arr[0] = sizeof(arr) / sizeof(arr[0]) - 1; 

arr[0].

Answer 4

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Answer 5

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int arrLen(int arr[])
{
    int size = 0;
    int* p = arr;
    while (*p != -1) {
        ++size;
        ++p;
    }
    return size;
}

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int arr[]={0,1,2,3,4,5, -1 };

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