Decimal places in package script

Question

echo off cls mode con: cols=55 lines=15 :MAIN color 07 cls set /p num1="Specify first number: " cls set /p num2="Specify second number: " cls set /a num3=%num1%*%num2% echo %num3% pause 

Say num1 = 30 and num2 = .10, then it will only display 0, not .3, since I can make it a decimal place and how could you display up to 5 decimal places if necessary?

Answer 1

The package does not support floating point arithmetic. You must rely on external scripts.

http://www.computing.net/howtos/show/batch-script-floating-point-math/753.html

Floating point separation in dos package

Answer 2

 ::turn all strings with decimals to integers to perform arithmetic ops ::does not error check for non-numerics or non-numeric formatting ::I check beforehand or it left as an exercise for the reader set mynum=12.34 call:str2dec num pos %mynum% echo str2dec num %num% , pos %pos% for %mynum% set mynum=12.3 call:str2dec num pos %mynum% echo str2dec num %num% , pos %pos% for %mynum% set mynum=12. call:str2dec num pos %mynum% echo str2dec num %num% , pos %pos% for %mynum% set mynum=12 call:str2dec num pos %mynum% echo str2dec num %num% , pos %pos% for %mynum% set mynum=.34 call:str2dec num pos %mynum% echo str2dec num %num% , pos %pos% for %mynum% GOTO:EOF :Str2Dec ::Str2Dec(retVal,decPlaces,strIn) ::returns the integer to %1 of strIn, %3, shifted %2 places to the left ::eg Str2Dec num pos 12.34 returns num=1234 pos=2 SET #=%3 SET lengthInput=0 SET decpoint= SET /A integerVal=0 SET /A shifted=0 :lenStr2Dec IF DEFINED # (SET #=%#:~1%&SET /A lengthInput+=1&GOTO:lenStr2Dec) IF !lengthInput! LSS 2 SET /A integerVal=%3&GOTO:xStr2Dec SET numString=%3 FOR /L %%x IN (1,1,!lengthInput!) DO ( SET /A startCharIndex=%%x-1 CALL SET nextChar=%%numString:~!startCharIndex!,1%% IF "!nextChar!" == "." ( SET decpoint=1 ) ELSE ( IF DEFINED decpoint SET /A shifted+=1 SET /A nextNum=!nextChar! SET /A integerVal*=10 SET /A integerVal+=!nextNum! ) ) :xStr2Dec SET "%~1=!integerVal!" SET "%~2=!shifted!" GOTO:EOF