Multiple wraps of cout "<<" using regex

Question

I can wrap cout with one occurrence of << , like this:

 cout<< "hey"; abc cin>>x; cout<< "hey";abc cin>>x; 

But I couldn’t wrap it correctly when it is something like this:

 cout<< "hey" << "men";abc cin>>x; cout<< "hey" <<"men"; abc 

Regex

 text = text.replace(/(cout\s*(&lt;&lt;[^;]*)+;)/g, '<span class="group">$1</span>'); 

See : http://jsfiddle.net/3N4AE/23/

Answer 1

Your problem was that semicolon in your regular expression also finds a semicolon in < special char.

Fixed using the following regular expression:

 /(cout\s*(<<.*?)[^(<)];)/g 

jsFiddle Demo