No, if you combine A into B, then at the end, branch A will only have changes A, and B will have changes A + B.
If you combine B into A, then A with have both A + B changes, and B will only have changes B.
Start:
/A1-A2-A3 X \B1-B2-B3
From A to B with Merge Lock:
/A1-A2-A3 X \B1-B2-B3-A*(1,2,3)
A to B fast forward:
/A1-A2-A3 X \A1-A2-A3-B1'-B2'-B3'
B in with merger fixation:
/A1-A2-A3-B*(B1,B2,B3) X \B1-B2-B3
B in fast forward:
/B1-B2-B3-A1'-A2'-A3' X \B1-B2-B3
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