Elixir range for arithmetic progression

Question

Is it possible to express arithmetic progression in a list without listing them all?

In Haskell, you can do this with a range function.

[2,4..10] == [2,4,6,8,10] 

Is there a similar way to do this with Elixir?

Answer 1

Stream.iterate / 2 does what you want:

 Stream.iterate(2, &(&1+2)) 

Answer 2

You can use the Erlang lists:seq function, from Elixir:

 :lists.seq(2,10,2) 

Answer 3

As I can see, there is a Stream.seq () stream added a month ago:

• Add Stream.seq () to create potentially infinite streams of values
• Add function range / step / seq