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PHP upload image file via url

I want to upload an image at a url like

'C:\wamp\www\reelstubs\app\webroot\img\movies\0bf522bb76777ba43393b9be5552b263.jpg'

But I need an array like

 array( 'name' => '', 'type' => '', 'tmp_name' => '', 'error' => (int) 4, 'size' => (int) 0 ),

Please suggest me how to get this?

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2 answers

You might need http://php.net/manual/en/function.file-get-contents.php and http://php.net/manual/en/function.file-put-contents.php

In combination, you can try:

 // Your file $file = 'C:\wamp\www\reelstubs\app\webroot\img\movies\0bf522bb76777ba43393b9be5552b263.jpg'; // Open the file to get existing content $data = file_get_contents($file); // New file $new = 'C:\wamp\www\reelstubs\app\webroot\img\movies\newimage.jpg'; // Write the contents back to a new file file_put_contents($new, $data);
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  The enctype attribute of the <form> tag specifies which content-type to use when submitting the form. "multipart/form-data" is used when a form requires binary data, like the contents of a file, to be uploaded so please use the post method for uploading a file because post method can handle unlimited data. but get method not not handle more than 8mb data . <html> <body> <form action="upload_file.php" method="post" enctype="multipart/form-data"> <label for="file">Filename:</label> <input type="file" name="file" id="file"><br> <input type="submit" name="submit" value="Submit"> </form> </body> </html> you can handle the array on upload_file.php page . upload_file.php <?php if ($_FILES["file"]["error"] > 0) { echo "Error: " . $_FILES["file"]["error"] . "<br>"; } else { echo "Upload: " . $_FILES["file"]["name"] . "<br>"; echo "Type: " . $_FILES["file"]["type"] . "<br>"; echo "Size: " . ($_FILES["file"]["size"] / 1024) . " kB<br>"; echo "Stored in: " . $_FILES["file"]["tmp_name"]; } ?>
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Source: https://habr.com/ru/post/1492608/

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