C ++ How to replace unusual quotes in code

Question

sometimes when you copy code from a document, it gets line numbers and strange quotes. I wrote a script to remove these seed numbers, but it is very difficult to find a way to remove these strange quotation marks "", so I included my full code. It reads the file and issues a formatted file. But the compiler warns that these quotes are multiple characters, which I think means non-standard ascii characters. It seems to work, but it is not a great solution. Any help appreciated:

#include <iostream> #include <fstream> #include <string> using namespace std; string replaceChar(string str, char ch1, char ch2); // Main int main(int argc, char *argv[]) { string line; fstream stri, stro; // ifstream in stri.open(argv[1], ios::in); if(stri.fail()){ cerr << "File failed to open for input" << endl; return 1; } // ofstream out stro.open("file_out.txt", ios::out); if(stro.fail()){ cerr << "File failed to open for output" << endl; return 1; } // Read - Write //stri.get(c); getline(stri, line, '\n'); while(!stri.eof()){ // Remove numbers line.erase(0,3); //line.replace( line.begin(), line.end(), "'", "\'" ); //line.replace( line.begin(), line.end(), "'", "\'" ); //line.replace( line.begin(), line.end(), """, "\'" ); //line.replace( line.begin(), line.end(), """, "\'" ); line = replaceChar(line, ''','\''); line = replaceChar(line, ''','\''); line = replaceChar(line, '"','\"'); line = replaceChar(line, '"','\"'); stro << line << endl; getline(stri, line, '\n'); } // Close files stri.close(); stro.close(); // Output cout << "File Edited Ok!"; //cout << count -1 << " characters copied."<< endl; } string replaceChar(string str, char ch1, char ch2) { for (int i = 0; i < str.length(); ++i) { if (str[i] == ch1) str[i] = ch2; } return str; } 

Answer 1

Well, this is not very, but it works. Anyone who wants to refine the search for one of these damned weird quotes will be my guest!

 #include <iostream> #include <fstream> #include <string> using namespace std; // Function Declaration bool replace(string& str, const string& from, const string& to); bool checkMyLine(string line); // Main int main(int argc, char *argv[]) { // line to edit string line; fstream stri, stro; // ifstream in stri.open(argv[1], ios::in); if(stri.fail()){ cerr << "File failed to open for input" << endl; return 1; } // ofstream out stro.open("file_out.txt", ios::out); if(stro.fail()){ cerr << "File failed to open for output" << endl; return 1; } // Read - Write while(getline(stri, line, '\n')){ // Remove numbers at start of each line followed by space, eg: "001: " int i; for(i = 0;i < line.length();i++) { if(line[i] == ' ') break; } line.erase(0,i+1); //Replace Odd Chars for(int i=0;i<line.length();i++) { replace(line, "\u2018","\u0027"); // replaces ' replace(line, "\u2019","\u0027"); // replaces ' replace(line, "\u201C","\u0022"); // replaces " replace(line, "\u201D","\u0022"); // replaces " } // Write to file stro << line << endl; } // Close files stri.close(); stro.close(); // Output Message cout << "File Edited Ok!"; }// End of Main // bool replace(string& str, const string& from, const string& to) { size_t start_pos = str.find(from); if(start_pos == string::npos) return false; str.replace(start_pos, from.length(), to); return true; } 

Answer 2

What type of script do you write to remove leading numbers? Do you have access to sed or tr ? They exist only for this kind of problem.

 sed -e 's/[''""]//g' 

No need to reinvent the wheel