I have a simple internet checker, but it sometimes returns an error that I can not handle ...
Here's the function:
def internet_on(): try: urllib2.urlopen("http://google.co.uk/", timeout = 10) return True except urllib2.URLError as e: return False except socket.timeout as e: return False
Here's the error:
Traceback (most recent call last): File "C:/Testscript.py", line 117, in internet_on urllib2.urlopen("http://google.co.uk/", timeout = 10) File "C:\Python27\lib\urllib2.py", line 127, in urlopen return _opener.open(url, data, timeout) File "C:\Python27\lib\urllib2.py", line 410, in open response = meth(req, response) File "C:\Python27\lib\urllib2.py", line 523, in http_response 'http', request, response, code, msg, hdrs) File "C:\Python27\lib\urllib2.py", line 442, in error result = self._call_chain(*args) File "C:\Python27\lib\urllib2.py", line 382, in _call_chain result = func(*args) File "C:\Python27\lib\urllib2.py", line 629, in http_error_302 return self.parent.open(new, timeout=req.timeout) File "C:\Python27\lib\urllib2.py", line 404, in open response = self._open(req, data) File "C:\Python27\lib\urllib2.py", line 422, in _open '_open', req) File "C:\Python27\lib\urllib2.py", line 382, in _call_chain result = func(*args) File "C:\Python27\lib\urllib2.py", line 1214, in http_open return self.do_open(httplib.HTTPConnection, req) File "C:\Python27\lib\urllib2.py", line 1187, in do_open r = h.getresponse(buffering=True) File "C:\Python27\lib\httplib.py", line 1045, in getresponse response.begin() File "C:\Python27\lib\httplib.py", line 409, in begin version, status, reason = self._read_status() File "C:\Python27\lib\httplib.py", line 373, in _read_status raise BadStatusLine(line) BadStatusLine: ''
How can I handle this error to return false, I want the internet_on function to return true if it connects, but if anything other than true, it should return false.