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How to compare the contents of two editors in bash?

Let's say there are two dirs

/path1 and /path2

eg

 /path1/bin /path1/lib /path1/... /path2/bin /path2/lib /path2/...

And you need to know if they are identical in content (file names and file contents), and if differences are not indicated .

How to do it on Linux? Is there a Bash / Zsh command for this?

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3 answers

The diff command can show all the differences between the two directories: diff -qr /path1 /path2

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Someone already suggested this, but deleted their answer, not knowing why. Try using rsync :

 rsync -avni /path1/ /path2

This program will usually synchronize the two folders, but with -n will perform a dry start instead.

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I use this script for such a task:

 diff <(cd "$dir1"; find . -type f -printf "%p %s\n" | sort) \ <(cd "$dir2"; find . -type f -printf "%p %s\n" | sort)

Feel free to customize the script in the <(...) for your specific needs. This version uses find to print the contents of a directory by printing the paths and file sizes found in it. Of course, other things are possible.

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Source: https://habr.com/ru/post/1480011/

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