I had 2 columns, one was the name of the supplier, the second was the address of the supplier, but it also had the name of the supplier. I needed to remove the name of the supplier, which would leave me with the address of the supplier without a name.
For example, if there was “Con Ed” in one column, the next column had “Con Ed 123 Street, New York, NY 11111”, I needed to replace “Con Ed” with zero and just have “123 Street, New York, NY 11111” in a collumn.
This is what I have done, and I will also let you know what you can do to achieve your goal.
First, I created a new column and set it to Length (using the LEN () function) of the provider name.
Then I created a new column and set it to length at the provider address.
The third column was also configured to use the Right () function. If the text is the supplier’s address and the length is the length of the address minus the length of the supplier’s name.
So think: "Con Ed 123 Street, New York, NY 11111" 1st column: (vendor length): len (Con Ed) = 6 2nd column: (vendor address length): len (Con Ed 123 Street , New York, NY 11111) = 37 3rd column: Right ([Supplier Address], 31 (37-6)) = ", New York, New York 11111"
Finally, I just applied the TRIM function to the third column.
In your case, you just want to use the Concatenate function to add the source column and the new column.
So, in the end you will have the following columns:
Column 1: Names: (Smith, Jones, Taylor)
Column 2: identifiers: (Smith_ID, Taylor_B, Jones_C)
Column 3: Flax ([Names])
Column 4: Flax ([ID])
Column5: Function "replace" = TRIM (on the right ([IDs], ([Column4] - [Column3]))
Column 6: Row inserted again = Merge ([Column3], [Column5])