How to get a domain name without www, subdomain and com / net / org / etc.

Question

I just need to get the domain name only from the url (without com and everything else):

I have:

http://www.subdomain.domain1.com/ www.subdomain.domain2.net subdomain.subdomain2.domain3.org/ http://domain4.com 

I want to get with PHP:

 domain1 domain2 domain3 domain4 

Answer 1

 $url="http://www.seventymm.co.in/browse/buy-home-furnishing-bed-sheets-pack-of-3/2456/1/v2034/0/0/1/2/1/0/go"; echo get_domain($url); function get_domain($url) { $urlobj=parse_url($url); $domain=$urlobj['host']; if (preg_match('/(?P<domain>[a-z0-9][a-z0-9\-]{1,63}\.[az\.]{2,6})$/i', $domain, $regs)) { return $regs['domain']; } return false; } 

Answer 2

parse_url ()

with argument "PHP_URL_HOST"

then explode () in the "." and extract the penultimate element of the resulting array

Answer 3

Based on Shyam's answer and using the concept suggested by Mark Baker to get the penultimate element of the namespace, I could suggest using a simpler regex using anchored lookup, as shown below:

 function get_domain($url) { $matches = []; preg_match('/[\w-]+(?=(?:\.\w{2,6}){1,2}(?:\/|$))/', $url, $matches); return $matches[0]; } 

Matches

• names at https://www.names.co.uk/
• domain1 at http://www.subdomain.domain1.com/
• domain2 at www.subdomain.domain2.net
• domain3 in subdomain.subdomain2.domain3.org/
• domain4 at http://domain4.com
• seventymm at http://www.seventymm.co.in/browse/buy-home-furnishing-bed-sheets-pack-of-3/2456/1/v2034/0/0/1/2/1/0/go

Answer 4

Shyam's answer is the best. You just need to make sure that all URLs start with HTTP and add strtok to the end (see below). Here's another version using an array:

 function get_domain($url) { $urlobj = parse_url($url); $domain = $urlobj['host']; if (preg_match('/(?P<domain>[a-z0-9][a-z0-9\-]{1,63}\.[az\.]{2,6})$/i', $domain, $regs)) { return $regs['domain']; } return false; } $urls = array( 'http://www.subdomain.domain1.com/', 'http://www.subdomain.domain2.net', 'http://subdomain.subdomain2.domain3.org/', 'http://domain4.com' ); // Using foreach + strtok to remove .[domain extensions] echo "<ul>"; foreach($urls as $url) { echo "<li>" . strtok(get_domain($url),'.') . "</li>"; } echo "</ul>"; 

This will output:

• domain1
• domain2
• DOMAIN3
• domain4

PS you can add strtok to a function as shown below:

 function get_domain($url) { $urlobj = parse_url($url); $domain = $urlobj['host']; if (preg_match('/(?P<domain>[a-z0-9][a-z0-9\-]{1,63}\.[az\.]{2,6})$/i', $domain, $regs)) { return strtok($regs['domain'], '.'); } return false; } 

then

 $urls = array( 'http://www.subdomain.domain1.com/', 'http://www.subdomain.domain2.net', 'http://subdomain.subdomain2.domain3.org/', 'http://domain4.com' ); // Using foreach echo "<ul>"; foreach($urls as $url) { echo "<li>" . get_domain($url) . "</li>"; } echo "</ul>"; 

Minus ul / li:

  $urls = array( 'http://www.subdomain.domain1.com/', 'http://www.subdomain.domain2.net', 'http://subdomain.subdomain2.domain3.org/', 'http://domain4.com' ); // Using foreach foreach($urls as $url) { echo get_domain($url)."<br>"; } 

Conclusion: vacation rental domain1
domain2
DOMAIN3
domain4

Answer 5

To get the domain, you can use $_SERVER["SERVER_NAME"] .

Expand the line with the subdomain that you do not want to include.

Eg. subdomain.domain.com

 <?php $add=explode('subdomain.',$_SERVER["SERVER_NAME"])[1]; // $add = domain.com ?>