Simple servlet project (HTTP status 404 error)

I want to create a servlet project.

My Java class is called AzpanaServlet.java and it contains an inner class. (When I compile it, I have 2 class files).

My project is a simple application that receives string input and does some things with it (it doesn't matter).

When I click the submit button, I get the following error:

 HTTP Status 404 - /AzpanaServlet Type Status report Message /AzpanaServlet Description The requested resource (/AzpanaServlet) is not available. Apache Tomcat/6.0.18 

Please help me if you can, I can’t solve this a lot of time. this is my java code:

 public class AzpanaServlet extends HttpServlet { // //Some functions // //Inner class: public class oneChar{...} // protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { /* * Get the value of form parameter */ String name = request.getParameter("name"); /* * Set the content type(MIME Type) of the response. */ response.setContentType("text/html"); String str = ""; PrintWriter out = response.getWriter(); ArrayList<Integer> list = new ArrayList<Integer>(); try { list = mainmanu(name); //not relevant function. } catch (Exception e) { str = e.toString(); e.printStackTrace(); } /* * Write the HTML to the response */ out.println("<html>"); out.println("<head>"); out.println("<title> this is your answers</title>"); out.println("</head>"); out.println("<body>"); if(str != ""){ out.println(str); } else{ for(int i = 0;i<=40;i++){ out.println(list.get(i)); out.println("<br>"); } } out.println("<a href='form.html'>"+"Click here to go back to input page "+"</a>"); out.println("</body>"); out.println("</html>"); out.close(); } public void destroy() { } } 

My web.xml code:

 <web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> <servlet> <servlet-name>AzpanaServlet</servlet-name> <servlet-class>com.example.AzpanaServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>AzpanaServlet</servlet-name> <url-pattern>/AzpanaServlet</url-pattern> </servlet-mapping> <welcome-file-list> <welcome-file>/form.html</welcome-file> </welcome-file-list> </web-app> 

My form.html code:

 <html> <head> <title>Zeev Project</title> </head> <body> <h1>Just Enter String</h1> <form method="POST" action="AzpanaServlet"> <label for="name">Enter String</label> <input type="text" id="name" name="name"/><br><br> <input type="submit" value="Submit Form"/> <input type="reset" value="Reset Form"/> </form> </body> </html> 

The folder hierarchy is as follows:

 ROOT[ WEB-INF[ web.xml classes[ com[ example[ AzpanaServlet.class AzpanaServlet$oneChar.class ] ] ] lib[ AzpanaServlet.java ] ] META-INF[ MANIFEST.MF ] form.html ] 
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3 answers

I copied your exact code and just commented on the servlet code

  protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { /* * Get the value of form parameter */ String name = request.getParameter("name"); System.out.println("Parameter name : "+name); 

It works like a charm.

In my server console

 Parameter name : helloo 

No problem with your configuration. You might want to clear your browser cache and try again.

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The problem may be that you are using the IDE to start Tomcat Server and are deployed in the context of the root application. Try using the application context for your application in your deployment. For example /myapp .

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Look at your IDE console or your tomcat log, has your web application ever really started?
For some reason this could not start.

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Source: https://habr.com/ru/post/1443973/


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