Int vs Double and division by zero exception

Question

We get a compile-time error when the integer is divided by zero, while in the case of double there is no compilation error, but at runtime we get the infinity / NaN as a result. Any idea why int and double have different behavior when divided by zero exception?

void Main() { int number = 20; var result1 = number/0; // Divide by zero compile time exception double doubleNumber = 20; var result2 = doubleNumber/0.0; // no compile time error. Result is infinity or NaN } 

Answer 1

Because it is as defined . If for integers there are no special values ​​for infinity and NaN, therefore, the compiler throws an error if it can detect a problem at compile time.

Answer 2

Due to their mathematical background. Infinity is defined for floating point numbers, but not for integers.

Answer 3

theoretically, division by zero should lead to infinity, but the integer data type has nothing to represent infinity. double data type, so there is no need to throw an exception there.