I have several floating point values ββwhen processing with decimal places exceeding 8 digits.
How can I round these values ββto tenths before using text() to draw them?
text()
You can format a floating point ( float or double ) x with two decimal places as follows:
float
double
x
String.format("%.2f", x)
This will give you a String .
String
For instance:
String.format("%.2f", 12.34567)
returns the string "12.35" .
"12.35"
Use the nf function described in http://processing.org/reference/nf_.html . The right option allows you to specify the number of decimal places to use.
Edit: I understand that I misunderstand your question; the function associated with it truncates, not a round. The quick answer gave me the following answer:
float round(float number, float decimal) { return (float)(round((number*pow(10, decimal))))/pow(10, decimal); }
suggested by Markavian in the subject: http://processing.org/discourse/yabb2/YaBB.pl?num=1115073288
Hope this helps.
You can also use DecimalFormat.
DecimalFormat myFormatter = new DecimalFormat("#.##"); String output = myFormatter.format(12.34567);
Check it out at docs.oracle.com
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