There is no answer for centuries, and I finally found it. So simple. Here he is:
Process p = new Process(); p.StartInfo.FileName = "file_name.jpg"; p.StartInfo.Verb = "Print"; p.Start();
Process p = new Process(); p.StartInfo.FileName = "file_name.jpg"; p.StartInfo.Verb = "Print"; p.Start();
Please note that the files must be .jpg , otherwise it can do something completely different or, most likely, nothing.
source share