In PHP, how do you know how many months have passed this month uptil today?

Question

Suppose today is February 21, 2011 (Monday). This is the third Monday of this month. If the date is indicated as input, how can I find out how many Mondays have passed before?

In PHP, how do you know how much has passed today this month?

Answer 1

$now=time() + 86400; if (($dow = date('w', $now)) == 0) $dow = 7; $begin = $now - (86400 * ($dow-1)); echo "Mondays: ".ceil(date('d', $begin) / 7)."<br/>"; 

works for me ....

EDIT: includes today and Monday.

Answer 2

This seems like a fairly simple division calculation. Subtract the number of days from past Mondays from the current date (example: wednesday = -2), divide it by 7 and ceil() to round it.

EDIT: This will include the current Monday in the room, returning "3" on Monday 21st.

Answer 3

You can scroll all days to the present day and count Mondays:

 $firstDate = mktime(0, 0, 0, date("n"), 1, date("Y")); $now = time(); $mondays = 0; for ($i = $firstDate; $i < $now; $i = $i + 24*3600) { if (date("D", $i) == "Mon") $mondays ++; } 

Not tested this script

Answer 4

  <?php function mondays_get($month, $stop_if_today = true) { $timestamp_now = time(); for($a = 1; $a < 32; $a++) { $day = strlen($a) == 1 ? "0".$a : $a; $timestamp = strtotime($month . "-$day"); $day_code = date("w", $timestamp); if($timestamp > $timestamp_now) break; if($day_code == 1) @$mondays++; } return $mondays; } echo mondays_get('2011-02'); 

I hope this is useful to you! I just rolled it.

"Beware of errors in the above code, I just proved it right, haven't tried it."

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Answer 5

Try it...

 //find the most recent monday (doesn't find today if today is Monday though) $startDate = strtotime( 'last monday' ); //if 'last monday' was not this month, 0 mondays. //if 'last monday' was this month, count the weeks $mondays = date( 'm', $startDate ) != date( 'm' ) ? 0 : floor( date( 'd', $startDate ) / 7 ); //increment the count if today is a monday (since strtotime didn't find it) if ( date( 'w' ) == 1 ) $mondays++; 

Answer 6

Another way is to find which day of the week today, find the first such day of the month through strtotime() magic, and then calculate the difference between this and now in weeks. See below a function that will accept Ymd formatted date() and return that day of the week of the month.

Note: strtotime must be verbose, including the “from” and the month: “first Monday 2011-02”, otherwise “it’s moving forward one day . This is a bit of me when I tested edge cases.

Also added some display pepper, which is completely optional, but I liked it.

 function nthWeekdayOfMonth($day) { $dayTS = strtotime($day) ; $dayOfWeekToday = date('l', $dayTS) ; $firstOfMonth = date('Y-m', $dayTS) . "-01" ; $firstOfMonthTS = strtotime($firstOfMonth) ; $firstWhat = date('Ym-d', strtotime("first $dayOfWeekToday of $monthYear", $firstOfMonthTS)) ; $firstWhatTS = strtotime($firstWhat) ; $diffTS = $dayTS - $firstWhatTS ; $diffWeeks = $diffTS / (86400 * 7); $nthWeekdayOfMonth = $diffWeeks + 1; return $nthWeekdayOfMonth ; } $day = date('Ym-d') ; $nthWeekdayOfMonth = nthWeekdayOfMonth($day) ; switch ($nthWeekdayOfMonth) { case 1: $inflector = "st" ; break ; case 2: $inflector = "nd" ; break ; case 3: $inflector = "rd" ; break ; default: $inflector = "th" ; } $dayTS = strtotime($day) ; $monthName = date('F', $dayTS) ; $dayOfWeekToday = date('l', $dayTS) ; echo "Today is the {$nthWeekdayOfMonth}$inflector $dayOfWeekToday in $monthName" ;