I need to split text separated by paragraph tag

Question

$text = "<p>this is the first paragraph</p><p>this is the first paragraph</p>"; 

I need to split this into an array, separated by paragraph tags. That is, I need to split this into an array with two elements:

 array ([0] = "this is the first paragraph", [1] = "this is the first paragraph") 

Answer 1

Remove the closing tags </p> , because we do not need them, and then explode the string into an array when opening the tags </p> .

 $text = "<p>this is the first paragraph</p><p>this is the first paragraph</p>"; $text = str_replace('</p>', '', $text); $array = explode('<p>', $text); 

To view the code run, see the next entry in the codec . As you can see, this code will leave you with an empty array entry at index 0. If this is a problem, then it can be easily removed by calling array_shift($array) before using the array.

Answer 2

For everyone who finds this, don't forget that the P tag can have styles, identifiers, or any other possible attributes, so you should probably look at something like this:

 $ps = preg_split('#<p([^>])*>#',$input); 

Answer 3

 $text = "<p>this is the first paragraph</p><p>this is the first paragraph</p>"; $exptext = explode("<p>", $text); echo $exptext[0]; echo "<br>"; echo $exptext[1]; 

//////////////// OUTPUT /////////////////

this is the first paragraph
this is the first paragraph

Answer 4

Try this code:

 <?php $textArray = explode("<p>" $text); for ($i = 0; $i < sizeof($textArray); $i++) { $textArray[$i] = strip_tags($textArray[$i]); } 

Answer 5

If your input is somewhat consistent, you can use a simple splitting method like:

  $paragraphs = preg_split('~(</?p>\s*)+~', $text, PREG_SPLIT_NO_EMPTY); 

If preg_split will look for combinations <p> and </p> plus possible spaces and select a line there.

As an unnecessary alternative, you can also use querypath or phpquery to extract only the full paragraph of the content using:

  foreach (htmlqp($text)->find("p") as $p) { print $p->text(); } 

Answer 6

Try the following:

 <?php $text = "<p>this is the first paragraph</p><p>this is the first paragraph</p>"; $array; preg_replace_callback("`<p>(.+)</p>`isU", function ($matches) { global $array; $array[] = $matches[1]; }, $text); var_dump($array); ?> 

This can be changed by placing the array in a class that manages it using the value value and getter methods.

Answer 7

Try it.

 <?php $text = "<p>this is the first paragraph</p><p>this is the first paragraph</p>"; $array = json_decode(json_encode((array) simplexml_load_string('<data>'.$text.'</data>')),1); print_r($array['p']); ?> 

Answer 8

This is an old question, but I could not find a reasonable solution in an hour of finding answers on stactverflow. If you have a line full of html tags (p tags), and if you want to get paragraphs (or the first paragraph), use DOMDocument .

$long_description is a string that contains <p> tags.

 $long_descriptionDOM = new DOMDocument(); // This is how you use it with UTF-8 $long_descriptionDOM->loadHTML((mb_convert_encoding($long_description, 'HTML-ENTITIES', 'UTF-8'))); $paragraphs = $long_descriptionDOM->getElementsByTagName('p'); $first_paragraph = $paragraphs->item(0)->textContent(); 

I guess this is the right decision. No need for regular expression. You should not use regex for parsing html.