How to load a Lua module as a string instead of a file?

Question

I am using LuaJava and C Code for Lua. What I'm trying to do is read the Lua source stored as a String resource in an Android application so that the Lua source code can be executed. I need to know how to do this using LuaJava or C.

I want to know how I can create a Lua module in Lua using String.

In other words, I save the Lua source, which will be stored in the .lua file in String. Then I want to load the contents of this line into Lua as an available module that can be called.

I see that there is a loadstring() function, but not sure how it will be called for LuaJava or C.

I do not want Lua to look for the file system for this file, I will find the file and convert it to a string. After I have the line, I need to know how to load a line copy of the contents of the file in Lua as a module that I can call.

I also want to know if, after calling loadstring(s) , if the module remains available for subsequent function calls without reloading loadstring() again.

Answer 1

If you need to load / compile a string from LuaJava, you can use the LuaState.LloadString(String source) function.

If you do not want to load the “module” from the source several times, you need to give it a name and save some flag in the table. You can even provide “unloading” so that you can load the module again from the source. It can be redefined in Lua as follows:

 do local loadedModules = {} -- local so it won't leak to _G function loadModule(name, source) if loadedModules[name] then return loadedModules[name] end loadedModules[name] = assert(loadstring(source))() or true end function unloadModule(name) loadedModules[name] = nil end end 

Answer 2

I'm not sure I understand this question, but here goes:

 local f = io.open(filename) local s = f:read '*a' -- read the entire contents of the file f:close() assert(loadstring(s))() -- parse and run string `s` as Lua code