Extract string and int from string

Question

I have a line: RoomA38 . I want to extract RoomA from it and put an object of type String, extract 3 and 8 and put them into two different types of int.I was thinking about splitting the method, but I don't know how to use this in this case. How can i do this?

Answer 1

Could you do something like this?

 String myString = "RoomA38"; StringBuilder sb = new StringBuilder(); List<Integer> numbers = new ArrayList<Integer>(); for(int i=0;i<myString.length();i++){ char c = myString.charAt(i); if(!Character.isDigit(c)){ sb.append(c); }else{ numbers.add(Integer.parseInt(c+"")); } } String roomString = sb.toString(); for(Integer i : numbers){ //use the number i } 

Answer 2

You can do this in different ways, you just need some kind of calculation, there are no specific api or build methods. You can also do this below.

  String str = "RoomA38"; int number = 0; String[] strArr = str.split("\\d"); str = str.replace(strArr[0], ""); number = Integer.parseInt(str); System.out.println("Numbers::: " + number); str = strArr[0]; System.out.println("String is:::: " + str); 

Answer 3

 public static void main(String[] args) { String str = "RoomA3814221"; String pattern = "[0-9]+"; Scanner sc = new Scanner(str); String result = sc.findInLine(pattern); String[] arr = result.split(""); System.out.println(result); System.out.println(arr.length); for (String s: arr) { System.out.println(s); } } 

Answer 4

You might want to use Scanner for this: http://docs.oracle.com/javase/6/docs/api/java/util/Scanner.html

Answer 5

using the following line, you can find out if char digit. Character.isDigit ('');

you can iterate over each char string in a string and extract useful characters accordingly.

Answer 6

You can extract Numbers from a string after that, write your own logic and to separate the numbers.

Thanks Sunil

Answer 7

if the format is always the same:

  String value = "RoomA38"; String room = value.substring(0, 5); Integer floor = Integer.valueOf(value.substring(5,6)); Integer roomNumber = Integer.valueOf(value.substring(6,7)); 

Answer 8

Why not use RegEx?

 @Test public void splitString() { final String src = "RoomA38"; final Pattern pattern = Pattern.compile("(\\D*)(\\d*)"); final Matcher matcher = pattern.matcher(src); matcher.matches(); final String resultString = matcher.group(1); final int resultInt = Integer.valueOf(matcher.group(2)); Assert.assertEquals("RoomA", resultString); Assert.assertEquals(38, resultInt); } 

Answer 9

Extract desired result using regex and pattern matching in java

 String chars; int result2,result3; String str= "RoomA38"; String regex ="([a-zA-Z]+)([0-9]{1})([0-9]{1})"; Matcher matcher = Pattern.compile( regex ).matcher( str); while (matcher.find( )) { result = matcher.group(1); result2 =Integer.parseInt(matcher.group(2)); result3 = Integer.parseInt(matcher.group(3)); System.out.println("chars="+result+" "+"number1="+result2+" "+"number2="+result3); } chars=RoomA number1=3 number2=8