Yes, the common problem is NP-Complete.
This is because Boolean algebra is modulo 2 arithmetic! Thus, any 3SAT formula can be rewritten as an equivalent arithmetic expression in modulo 2 arithmetic. Checking the correctness of the 3SAT formula is equivalent to checking whether the corresponding arithmetic expression can be 1 or not.
For example, abb becomes ab in arithmetic. NOT a is 1-a etc.
But in your case, talking about NP-Compleness does not make sense, since this is one specific problem.
Also, lhf is correct. You can use the Hansel lifting lemma. The main point is that for the solution P(x) = 0 mod 2^(e+1) we can solve P(x) = 0 mod 2^e and "raise" these solutions to mod 2^(e+1)
Here is a pdf explaining how to use this: http://www.cs.xu.edu/math/math302/04f/PolyCongruences.pdf
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