Bytes and integers and concatenation and python

Question

I have 2 32 bit unsigned integers.

777007543 and 114997259

and a string of bytes.

0x47 0x30 0x22 0x2D 0x5A 0x3F 0x47 0x58

How do I get python to give me a concatenation of these 3 such that I have ...

0x2E 0x50 0x31 0xB7 0x06 0xDA 0xB8 0x0B 0x47 0x30 0x22 0x2D 0x5A 0x3F 0x47 0x58

Then I would run this through the md5 hash and I get ...

0x30 0x73 0x74 0x33 0x52 0x6C 0x26 0x71 0x2D 0x32 0x5A 0x55 0x5E 0x77 0x65 0x75

If anyone can run this through python code would be greatly appreciated

Answer 1

import struct import hashlib x = struct.pack('>II8B', 777007543, 114997259, 0x47, 0x30, 0x22, 0x2D, 0x5A, 0x3F, 0x47, 0x58) hash = hashlib.md5(x).digest() print [hex(ord(d)) for d in x] (output) ['0x2e', '0x50', '0x31', '0xb7', '0x6', '0xda', '0xb8', '0xb', '0x47', '0x30', '0x22', '0x2d', '0x5a', '0x3f', '0x47', '0x58'] print [hex(ord(d)) for d in hash] (output) ['0x30', '0x73', '0x74', '0x33', '0x52', '0x6c', '0x26', '0x71', '0x2d', '0x32', '0x5a', '0x55', '0x5e', '0x77', '0x65', '0x75'] 

Answer 2

 q = hex(777007543) + hex(114997259)[2:] + '4730222d5a3f4758' 

just do it. this is why it works:

 >>> num1, num2 (777007543, 114997259) >>> hex(num1), hex(num2) ('0x2e5031b7', '0x6dab80b') >>> hex(num1) + hex(num2) + '0x4730222d5a3f4758' '0x2e5031b70x6dab80b0x4730222d5a3f4758' >>> hex(num1) + hex(num2)[2:] + '4730222d5a3f4758' '0x2e5031b76dab80b4730222d5a3f4758' >>> int(_, 16) 3847554995347152223960862296285071192L 

It’s not difficult, however, to deal with the view that you showed in your answer if you want

edit:

that's what scott griffhits said. He is right;)

"

Using hex only works here because the numbers are big enough to require 8 hex digits. We need to use the format for the example '{0:08x}{1:08x}'.format(num1, num2) will fill the six to eight zeros.

"

Answer 3

This will give you a list of all the values ​​you want,

 >>> [777007543 >> i & 0xff for i in xrange(24,0,-8)] + \ ... [114997259 >> i & 0xff for i in xrange(24,0,-8)] + \ ... map(ord, stringofbytes) 

or even better (from another thread that you started),

 >>> struct.unpack('>12B', \ ... struct.pack('>L', 777007543) + struct.pack('>L', 114997259) + '.P1\xb7') 

If you want to make this a string to go to your md5 hash,

 >>> map(chr, _) 

I assume that each byte of the string should represent a 1-byte number.