An insecure thread means that if multiple threads try to access an object at the same time, something can change from one access to another and cause problems. Consider the following:
int incrementCount() { this.count++;
will not be thread safe. Why not? Imagine that thread 1 accesses it, count increases, then some processing happens. Having passed through a function, another thread calls it, increasing count again. The first stream from which he could go, say, from 1 to 2, will now have him from 1 to 3 when he returns. Topic 2 will see that it goes from 1 to 3, so what happened to 2?
In this case, you would like something like this (bearing in mind that this is not some language-specific code, but closest to Java, one of the 2 I worked with)
int incrementCount() synchronized { this.count++;
The synchronized should ensure that as long as one thread accesses it, no other threads can. This would mean that thread 1 gets into it, count goes from 1 to 2, as expected. Thread 2 gets into it, while 1 is processing, it should wait for thread 1 to complete. When this is done, thread 1 will receive a return of 2, then thread 2 will go to the checkmark and get the expected value of 3.
Now, an example similar to what you have, it will be completely thread safe, no matter what:
int incrementCount(int count) { count++;
Since the only variables affected here are completely local to this function, there is no case when two threads accessing it at the same time can try to work with data modified from another. This will make the thread safe.
So, to answer the question, assuming that the functions do not change anything outside the specific function being called, then yes, the class can be considered thread safe.