Display a list of items vertically in the table instead of horizontal

Question

I have a list of items sorted alphabetically:

mylist = [a,b,c,d,e,f,g,h,i,j] 

I can display the list in the html table horizontally, for example:

 | a , b , c , d | | e , f , g , h | | i , j , , | 

Which algorithm for creating a table vertically looks like this:

 | a , d , g , j | | b , e , h , | | c , f , i , | 

I use python, but your answer can be in any language or even pseudo-code.

Answer 1

 >>> l = [1,2,3,4,5,6,7,8,9,10] >>> [l[i::3] for i in xrange(3)] [[1, 4, 7, 10], [2, 5, 8], [3, 6, 9]] 

Replace 3 with the number of rows you want as a result:

 >>> [l[i::5] for i in xrange(5)] [[1, 6], [2, 7], [3, 8], [4, 9], [5, 10]] 

Answer 2

 import itertools def grouper(n, iterable, fillvalue=None): # Source: http://docs.python.org/library/itertools.html#recipes "grouper(3, 'ABCDEFG', 'x') --> ABC DEF Gxx" return itertools.izip_longest(*[iter(iterable)]*n,fillvalue=fillvalue) def format_table(L): result=[] for row in L: result.append('| '+', '.join(row)+' |') return '\n'.join(result) L = ['a','b','c','d','e','f','g','h','i','j'] L_in_rows=list(grouper(3,L,fillvalue=' ')) L_in_columns=zip(*L_in_rows) print(format_table(L_in_columns)) # | a, d, g, j | # | b, e, h, | # | c, f, i, | 

Answer 3

Here is a rough solution that works (prints numbers from 0 to N-1 inclusive):

 import math NROWS = 3 N = 22 for nr in xrange(NROWS): for nc in xrange(int(math.ceil(1.0 * N/NROWS))): num = nc * NROWS + nr if num < N: print num, print '' 

This is just typing numbers, for example with NROWS = 3 and N = 22 :

 0 3 6 9 12 15 18 21 1 4 7 10 13 16 19 2 5 8 11 14 17 20 

You can easily adapt it to print everything you want and add the formatting you need.

Answer 4

 int array_size = 26; int col_size = 4; for (int i = 0; i <= array_size/col_size; ++i) { for (int j = i; j < array_size; j += col_size-1) { print (a[j]); } print("\n"); } 

Answer 5

This is how I do it. Given a list of l (integers, in the example).

• Determine the number of columns (or rows) and
• Calculate the number of rows (or columns).
• Then scroll them along the line and type in the appropriate value.

See the code below:

 import math l = [0,1,2,3,4,5,6,7,8,9] num_cols=4 num_rows=int(math.ceil(1.0*len(l)/num_cols)) for r in range(num_rows): for c in range(num_cols): i = num_rows*c + r if i<len(l): print '%3d ' % l[i], else: print ' - ', # no value print # linebreak 

Best

Philip

Answer 6

 >>> import numpy as np >>> L=['a','b','c','d','e','f','g','h','i','j'] >>> width=4 >>> height = (len(L)-1)/width+1 >>> L=L+[' ']*(width*height-len(L)) #Pad to be even multiple of width >>> A = np.array([L]) >>> A.shape=(width,height) >>> A.transpose() array([['a', 'd', 'g', 'j'], ['b', 'e', 'h', ' '], ['c', 'f', 'i', ' ']], dtype='|S1')