How to get the project path during development

Question

I am using the component (System.ComponentModel.Component), and I want to get the application path to my project in order to create a file in it.

thanks

Florian

Answer 1

The only thing that seemed to work (sequentially) for me was to get EnvDTE.DTE (from IServiceProvider, which you get from EditValue ()), i.e.:

EnvDTE.DTE dte = envProvider.GetService(typeof(EnvDTE.DTE)) as EnvDTE.DTE; string dir = Path.GetDirectoryName(dte.Solution.FullName); 

When I tried to use Assembly.GetXAssembly, I got a temporary path that VS uses during development.

Answer 2

Use AppDomain.CurrentDomain.BaseDirectory.

Answer 3

It works?

  New Uri(Assembly.GetCallingAssembly().CodeBase).AbsolutePath 

("CallingAssembly" because you can put a method to get the execution path to the service level (assembly))

Answer 4

Take a look: The path to the Project (bin) folder at compile time?

With this technique, you can “Create” (once) and then use the generated file to get the project location in DesignTime. This will work regardless of the workspace.

Answer 5

I think Robert is almost right.

It works:

 Path.GetDirectoryName(Assembly.GetExecutingAssembly().Location) 

Answer 6

 string solutionpath = Directory.GetParent(Application.ExecutablePath).Parent.Parent.Parent.FullName; 

I think this is the best solution because you do not need to add any library more than "Using System.IO" :)

Answer 7

I did a simple test (as a temporary project, I added a string property to store the current directory value) (I do not describe the whole process of data binding. See part of my development time / binding time message)

In the empty constructor of the main window of the ViewModel class (dedicated to design time binding)

 public MainWindow_ViewModel():this(null) { dtpath = Directory.GetCurrentDirectory(); Console.WriteLine("CTor finished"); } 

In the mainwindow.xaml file, I added a text box to display the result (do not pay attention to the value of the grid line)

 <TextBox Text="{Binding dtpath}" Grid.Row="3"/> 

And I got an idea about VS design (as Florian commented, but with a newer value after 4 years): C: \ Program Files (x86) \ Microsoft Visual Studio 14.0 \ Common7 \ IDE

Answer 8

Just call GetMyPath, which is defined as

 string GetMyPath([CallerFilePath] string from = null) { return from; } 

Answer 9

If you're talking about a WPF designer, use the Context Type property / type

Details: - During development, you have an instance of modelItem (suppose you know this), if not, then you can create an instance of it in the Override implementation of the Activate method

// in class DesignAdorner

 public class DesignAdorner : PrimarySelectionAdornerProvider { protected override void Activate(ModelItem item) { modelItem = item; } } 

Now you can access the current application path using the following code with one line

 string aplicationPathDir = System.IO.Directory.GetParent(modelItem.Context.ToString()).FullName; 

Let me know if this does not help you.