How to get table schema name

Question

I am using SQL Server 2008 and have the following query:

SELECT SO1.name AS Tab, SC1.name AS Col, SO2.name AS RefTab, SC2.name AS RefCol, FO.name AS FKName FROM dbo.sysforeignkeys FK INNER JOIN dbo.syscolumns SC1 ON FK.fkeyid = SC1.id AND FK.fkey = SC1.colid INNER JOIN dbo.syscolumns SC2 ON FK.rkeyid = SC2.id AND FK.rkey = SC2.colid INNER JOIN dbo.sysobjects SO1 ON FK.fkeyid = SO1.id INNER JOIN dbo.sysobjects SO2 ON FK.rkeyid = SO2.id INNER JOIN dbo.sysobjects FO ON FK.constid = FO.id 

How to get table schema name?

thanks for the help

Answer 1

Use OBJECT_SCHEMA_NAME

 SELECT OBJECT_SCHEMA_NAME(f.parent_object_id) AS TableNameSchema, -- this OBJECT_NAME(f.parent_object_id) AS TableName, COL_NAME(fc.parent_object_id,fc.parent_column_id) AS ColumnName, OBJECT_SCHEMA_NAME(f.referenced_object_id) AS ReferenceTableNameSchema, OBJECT_NAME (f.referenced_object_id) AS ReferenceTableName, COL_NAME(fc.referenced_object_id,fc.referenced_column_id) AS ReferenceColumnName, f.name AS ForeignKey FROM sys.foreign_keys AS f INNER JOIN sys.foreign_key_columns AS fc ON f.OBJECT_ID = fc.constraint_object_id INNER JOIN sys.objects AS o ON o.OBJECT_ID = fc.referenced_object_id 

Answer 2

According to Sql Server 2008:

  SELECT Object_name(f.parent_object_id) AS TableName, Col_name(fc.parent_object_id, fc.parent_column_id) AS ColumnName, Object_name (f.referenced_object_id) AS ReferenceTableName, Col_name(fc.referenced_object_id, fc.referenced_column_id) AS ReferenceColumnName, f.name AS ForeignKey, Quotename(Schema_name(f.schema_id)) + '.' + Quotename( Object_name(f.parent_object_id)) AS schemaname, Quotename(Schema_name(o.schema_id)) + '.' + Quotename( Object_name(f.referenced_object_id)) AS ReferenceSchemaName FROM sys.foreign_keys AS f INNER JOIN sys.foreign_key_columns AS fc ON f.OBJECT_ID = fc.constraint_object_id INNER JOIN sys.objects AS o ON o.OBJECT_ID = fc.referenced_object_id 

If you need to know a schema name based on object_id , then use OBJECT_SCHEMA_NAME() , if you want to get a schema name based on schema_id , then use SCHEMA_NAME() .