F #, Forward a match case without using a temporary variable

Question

I would like to redirect the variable to a match case without using the temp variable or lambda. Idea:

let temp = x |> Function1 |> Function2 // ........ Many functions later. |> FunctionN let result = match temp with | Case1 -> "Output 1" | Case2 -> "Output 2" | _ -> "Other Output" 

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Hope to write something similar to the following:

 // IDEAL CODE (with syntax error) let result = x |> Function1 |> Function2 // ........ Many functions later. |> FunctionN |> match with // Syntax error here! Should use "match something with" | Case1 -> "Output 1" | Case2 -> "Output 2" | _ -> "Other Output" 

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The closest I have is using lambda. But I think the code below is not very good, because I will still “name” the temporary variable.

 let result = x |> Function1 |> Function2 // ........ Many functions later. |> FunctionN |> fun temp -> match temp with | Case1 -> "Output 1" | Case2 -> "Output 2" | _ -> "Other Output" 

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On the other hand, I can directly replace the temp variable with a large piece of code:

 let result = match x |> Function1 |> Function2 // ........ Many functions later. |> FunctionN with | Case1 -> "Output 1" | Case2 -> "Output 2" | _ -> "Other Output" 

Can I write code similar to Code # 2? Or do I need to select code number 3 or number 4? Thanks.

Answer 1

 let result = x |> Function1 |> Function2 // ........ Many functions later. |> FunctionN |> function | Case1 -> "Output 1" | Case2 -> "Output 2" | _ -> "Other Output"