Here's a shorter code for Problem 1 :
upstream_seq = 'ATACATTGGCCTTGGCTTAGACTTAGATCTAGACCTGAAAATAACCTGCCGAAAAGACCCGCCCGACTGTTAATACTTTACGCGAGGCTCACCTTTTTGTTGTGCTCCC' downstream_seq = 'ATACACGAAAAGCGTTCTTTTTTTGCCACTTTTTTTTTATGTTTCAAAACGGAAAATGTCGCCGTCGTCGGGAGAGTGCCTCCTCTTAGTTTATCAAATAAAGCTTTCG' common_prefix = '' for x,y in zip(upstream_seq, downstream_seq): if x == y: common_prefix += x else: break print(common_prefix)
The naive approach for Problem 2 would be to simply generate a set of each substring for each row, calculate their intersection and sort by length:
upstream_seq = 'ATACATTGGCCTTGGCTTAGACTTAGATCTAGACCTGAAAATAACCTGCCGAAAAGACCCGCCCGACTGTTAATACTTTACGCGAGGCTCACCTTTTTGTTGTGCTCCC' downstream_seq = 'ATACACGAAAAGCGTTCTTTTTTTGCCACTTTTTTTTTATGTTTCAAAACGGAAAATGTCGCCGTCGTCGGGAGAGTGCCTCCTCTTAGTTTATCAAATAAAGCTTTCG' def all_substrings(string): n = len(string) return {string[i:j+1] for i in range(n) for j in range(i,n)} print(all_substrings('ABCA')) # {'CA', 'BC', 'ABC', 'C', 'BCA', 'AB', 'A', 'B', 'ABCA'} print(all_substrings(upstream_seq) & all_substrings(downstream_seq)) # {'AAAG', 'CA', 'A', 'AAC', 'TGTT', 'ACT', 'CTTAG', 'GCT', 'ATAC', 'AAAA', 'TTTA', 'AAT', 'GTGC', 'CTT', 'AAAAG', 'TTTG', 'CGAA', 'AA', 'CGAAAAG', 'GCC', 'ACA', 'TGCC', 'AAATAA', 'CTCC', 'TTTTT', 'CGCC', 'CAC', 'GAG', 'CTC', 'CGAAAA', 'ATC', 'TCA', 'GA', 'CGC', 'TGT', 'GT', 'GC', 'GAAA', 'ACTTT', 'AAG', 'TTTT', 'CT', 'AATA', 'TCC', 'CGAAA', 'GAA', 'GAAAAG', 'GTT', 'AG', 'TC', 'AAAAT', 'CC', 'TTT', 'AATAA', 'CTTTT', 'ACTT', 'TTA', 'CTTT', 'GCTT', 'GCCG', 'GTG', 'TACA', 'TT', 'GCG', 'TTTTTG', 'TAG', 'TTG', 'TTAG', 'AAATA', 'CTTTTT', 'AAAT', 'TAA', 'ACG', 'TG', 'GCCT', 'G', 'TAC', 'CCT', 'TCT', 'ATA', 'CTTA', 'CCG', 'CG', 'ATAA', 'GG', 'ATACA', 'AGA', 'TGC', 'C', 'T', 'AT', 'GAAAA', 'CGA', 'GAAAAT', 'TA', 'AC', 'AAA', 'TTTTG'} print(max(all_substrings(upstream_seq) & all_substrings(downstream_seq), key=len)) # CGAAAAG
If you want a more efficient approach, you should use a suffix tree .
If you don't want to reinvent the wheel, you can simply use difflib.SequenceMatcher.find_longest_match