How to get the parent folder name of the current directory?

Question

I know that there are functions for finding the parent directory or path, for example.

os.path.dirname(os.path.realpath(__file__)) 

'C: \ Users \ JAHON \ Desktop \ Projects \ CAA \ Result \ CAA \ project_folder'

Is there a function that just returns the name of the parent folder? In this case, it should be project_folder .

Answer 1

You can get the last part of any path using basename (from os.path ):

 >>> from os.path import basename >>> basename('/path/to/directory') 'directory' 

Just note that if your path ends with / , then the last part of the path is empty:

 >>> basename('/path/to/directory/') '' 

Answer 2

You can easily achieve this with os

 import os os.path.basename(os.getcwd()) 

Answer 3

Yes, you can use PurePath .

 PurePath(__file__).parent.name == 'parent_dir'