Using the following code, I can remove the horizontal lines in the images. See the result below.
import cv2 from matplotlib import pyplot as plt img = cv2.imread('image.png',0) laplacian = cv2.Laplacian(img,cv2.CV_64F) sobelx = cv2.Sobel(img,cv2.CV_64F,1,0,ksize=5) plt.subplot(2,2,1),plt.imshow(img,cmap = 'gray') plt.title('Original'), plt.xticks([]), plt.yticks([]) plt.subplot(2,2,2),plt.imshow(laplacian,cmap = 'gray') plt.title('Laplacian'), plt.xticks([]), plt.yticks([]) plt.subplot(2,2,3),plt.imshow(sobelx,cmap = 'gray') plt.title('Sobel X'), plt.xticks([]), plt.yticks([]) plt.show()

The result is pretty good, not perfect, but good. What I want to achieve is what has been shown here . I am using this code .
Original Image .. 
One of my questions: how to save Sobel X without applying a gray effect? Like the original, but crafted ..
Also, is there a better way to do this?
EDIT
Using the following code for the source image is good. It works pretty well.
import cv2 import numpy as np img = cv2.imread("image.png") img=cv2.cvtColor(img,cv2.COLOR_BGR2GRAY) img = cv2.bitwise_not(img) th2 = cv2.adaptiveThreshold(img,255, cv2.ADAPTIVE_THRESH_MEAN_C,cv2.THRESH_BINARY,15,-2) cv2.imshow("th2", th2) cv2.imwrite("th2.jpg", th2) cv2.waitKey(0) cv2.destroyAllWindows() horizontal = th2 vertical = th2 rows,cols = horizontal.shape #inverse the image, so that lines are black for masking horizontal_inv = cv2.bitwise_not(horizontal) #perform bitwise_and to mask the lines with provided mask masked_img = cv2.bitwise_and(img, img, mask=horizontal_inv) #reverse the image back to normal masked_img_inv = cv2.bitwise_not(masked_img) cv2.imshow("masked img", masked_img_inv) cv2.imwrite("result2.jpg", masked_img_inv) cv2.waitKey(0) cv2.destroyAllWindows() horizontalsize = int(cols / 30) horizontalStructure = cv2.getStructuringElement(cv2.MORPH_RECT, (horizontalsize,1)) horizontal = cv2.erode(horizontal, horizontalStructure, (-1, -1)) horizontal = cv2.dilate(horizontal, horizontalStructure, (-1, -1)) cv2.imshow("horizontal", horizontal) cv2.imwrite("horizontal.jpg", horizontal) cv2.waitKey(0) cv2.destroyAllWindows() verticalsize = int(rows / 30) verticalStructure = cv2.getStructuringElement(cv2.MORPH_RECT, (1, verticalsize)) vertical = cv2.erode(vertical, verticalStructure, (-1, -1)) vertical = cv2.dilate(vertical, verticalStructure, (-1, -1)) cv2.imshow("vertical", vertical) cv2.imwrite("vertical.jpg", vertical) cv2.waitKey(0) cv2.destroyAllWindows() vertical = cv2.bitwise_not(vertical) cv2.imshow("vertical_bitwise_not", vertical) cv2.imwrite("vertical_bitwise_not.jpg", vertical) cv2.waitKey(0) cv2.destroyAllWindows() #step1 edges = cv2.adaptiveThreshold(vertical,255, cv2.ADAPTIVE_THRESH_MEAN_C,cv2.THRESH_BINARY,3,-2) cv2.imshow("edges", edges) cv2.imwrite("edges.jpg", edges) cv2.waitKey(0) cv2.destroyAllWindows() #step2 kernel = np.ones((2, 2), dtype = "uint8") dilated = cv2.dilate(edges, kernel) cv2.imshow("dilated", dilated) cv2.imwrite("dilated.jpg", dilated) cv2.waitKey(0) cv2.destroyAllWindows() # step3 smooth = vertical.copy() #step 4 smooth = cv2.blur(smooth, (4,4)) cv2.imshow("smooth", smooth) cv2.imwrite("smooth.jpg", smooth) cv2.waitKey(0) cv2.destroyAllWindows() #step 5 (rows, cols) = np.where(img == 0) vertical[rows, cols] = smooth[rows, cols] cv2.imshow("vertical_final", vertical) cv2.imwrite("vertical_final.jpg", vertical) cv2.waitKey(0) cv2.destroyAllWindows()

But if I have this image?

I tried to execute the above code and the result is really bad ...

Other images I'm working on are ...


