How to combine float to nearest int in C #?

Question

In C #, how do I combine a float with the closest int?

I see Math.Ceiling and Math.Round, but they return a decimal number. Do I use one of them and then apply to Int?

Answer 1

If you want to round to the nearest int:

int rounded = (int)Math.Round(precise, 0); 

You can also use:

 int rounded = Convert.ToInt32(precise); 

which will use Math.Round(x, 0); for rounding and throwing for you. It looks neater, but a little less clear. IMO.

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If you want to round up :

 int roundedUp = (int)Math.Ceiling(precise); 

Answer 2

Above my head:

 float fl = 0.678; int rounded_f = (int)(fl+0.5f); 

Answer 3

(int) Math.Round (myNumber, 0)

Answer 4

The easiest way is to simply add 0.5f to it and then apply it to int.

Answer 5

Do I use one of them and then apply to Int?

Yes. It's not a problem. Decimals and doubles can accurately represent integers, so there will be no representation error. (You will not get a case, for example, where Round returns 4.999 ... instead of 5.)

Answer 6

You can apply to int if you are sure that it is in the range for int (Int32.MinValue - Int32.MaxValue).