A regular expression to match words (url) only if it does not contain a character

Question

I use an API that sometimes truncates links inside the text that it returns, and instead of "longtexthere https://fancy.link " get get longtexthere https: // fa ... ".

I try to find the link only if it is complete or, in other words, does not contain the symbol "...".

So far I can get the links using the following regular expression:

((?:https?:)?\/\/\S+\/?) 

but obviously it returns every link, including broken ones.

I tried to do something like this:

 ((?:https?:)?\/\/(?:(?!…)\S)+\/?) 

Although it began to ignore the symbol "...", it still returned the link, but without including the symbol, so in the case of " https: // fa ..." it returned " https: // fa , whereas I just want so that he ignores this broken link and goes over.

Fought this watch and just could not lower his head. :(

Thanks for any help in advance.

Answer 1

you can use

 (?:https?:)?\/\/[^\s…]++(?!…)\/? 

See the demo version of regex . The possessive quantifier [^\s…]++ will match all characters without spaces and not … without subsequent backtracking, and then check if the next character is … If so, no match will be found.

Alternatively, if your regex engine allows possessive quantifiers, use a negative lookup :

 (?!\S+…)(?:https?:)?\/\/\S+\/? 

Watch another demo version of regex . Appearance (?!\S+…) will not match if the characters <+> << → <1>

Answer 2

Try:

  ((?:https?:)?\/\/\S+[^ \.]{3}\/?) 

This is the same as your original template .. you just say that the last three characters should not be. (period) or '' (space)

UPDATE: Your second link worked.

and if you tweak your regex slightly, it will do what you want:

  ((?:https?:)?\/\/\S+[^ …] \/?) 

Yes, it looks like what you had there, except that I added a “space” after the part that we don’t want. This will make the regular expression match until it contains a space, url, which has the character "...". Without space at the end, it will match until it includes "...", so it did not do what we wanted;)

Answer 3

You can try the following regex

 https?:\/\/\w+(?:\.\w+\/?)+(?!\.{3})(\s|$) 

See demo https://regex101.com/r/bS6tT5/3

Answer 4

Try:

 https?:\/\/[^ ]*?…|(https?:\/\/[^ ]+\.[^ ]+) 

Here is a demon.