I have been looking at this for several hours, and I cannot find a solution. I just do not understand.
I have a parent who has many children. I created a view that allows me to get all the parent children. Now I want to finish this list and make a PATCH for parents with a new list of children. I understand that I need to write my own update method, but I cannot figure out how to do this.
Here is my child serializer:
class ChildSerializer(serializers.HyperlinkedModelSerializer): class Meta: model = models.Child fields = ('id', 'url', 'name',)
Here is my parent serializer:
class ParentSerializer(serializers.HyperlinkedModelSerializer): children = ChildSerializer(many=True) class Meta: model = models.Parent fields = ('id', 'url', 'name', 'children',) def update(self, instance, validated_data): submitted_children = validated_data.get('children') if submitted_children: for child in submitted_children: child_instance = Child.objects.get(id=child.id) instance.children.add(child_instance) instance.save() return instance
My understanding of what is about to happen is ...
- Get sent children
validated_data.pop('children') - Scroll through them and add each one to parent.children many to many
- Save Parent Model
I probably tried a few dozen different ideas here, but I can't get it to work. The above code does not change children_set.
Any suggestions are welcome.
For reference, I studied the following:
http://www.django-rest-framework.org/api-guide/serializers/#saving-instances
http://www.django-rest-framework.org/api-guide/serializers/#writable-nested-representations
http://www.django-rest-framework.org/api-guide/serializers/#validation
django rest framework a lot for many json write
And a bunch more, but I can’t remember them right now
UPDATE:
[{"id": 2, "url": " http://127.0.0.1:8000/api/v1/children/2 ", "first_name": "Tom", "last_name": "Jones", "date_of_birth ":" 1969-03-14 "}]