Curl File Download Stream

Question

I am doing the following on Windows MS-DOS.

In "inspect-> Copy as cURL (cmd)" Chrome to track file download returns me:

curl "http://up11.usersfiles.com/cgi-bin/upload.cgi?upload_id=303797686054&js_on=1&utype=anon&upload_type=file" -H "Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8" -H "Referer: http://usersfiles.com/" -H "Origin: http://usersfiles.com" -H "Upgrade-Insecure-Requests: 1" -H "User-Agent: Mozilla/5.0 (Windows NT 6.2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/48.0.2564.116 Safari/537.36" -H "Content-Type: multipart/form-data; boundary=----WebKitFormBoundaryKWLS1B0x6JrGdgBM" --data-binary "------WebKitFormBoundaryKWLS1B0x6JrGdgBM"^ "Content-Disposition: form-data; name=""upload_type"""^ "file"^ "------WebKitFormBoundaryKWLS1B0x6JrGdgBM"^ "Content-Disposition: form-data; name=""sess_id"""^ "------WebKitFormBoundaryKWLS1B0x6JrGdgBM"^ "Content-Disposition: form-data; name=""srv_tmp_url"""^ "http://up11.usersfiles.com/tmp"^ "------WebKitFormBoundaryKWLS1B0x6JrGdgBM"^ "Content-Disposition: form-data; name=""file_0""; filename=""prueba.mp4"""^ "Content-Type: video/mp4"^ "------WebKitFormBoundaryKWLS1B0x6JrGdgBM"^ "Content-Disposition: form-data; name=""undefined_descr"""^ "------WebKitFormBoundaryKWLS1B0x6JrGdgBM"^ "Content-Disposition: form-data; name=""link_rcpt"""^ "------WebKitFormBoundaryKWLS1B0x6JrGdgBM"^ "Content-Disposition: form-data; name=""link_pass"""^ "------WebKitFormBoundaryKWLS1B0x6JrGdgBM"^ "Content-Disposition: form-data; name=""to_folder"""^ "------WebKitFormBoundaryKWLS1B0x6JrGdgBM"^ "Content-Disposition: form-data; name=""file_1""; filename="""""^ "Content-Type: application/octet-stream"^ "------WebKitFormBoundaryKWLS1B0x6JrGdgBM"^ "Content-Disposition: form-data; name=""submit_btn"""^ " Start Upload "^ "------WebKitFormBoundaryKWLS1B0x6JrGdgBM--"^ "" --compressed 

This does not work on Windows in MS-DOS, how can I make it work for me? I am not sure how to use -data-binary. could you help me?