JavaScript enforcement type

Question

I assume that I know the differences between == and === in JavaScript, this is what == will do type coercion when comparing, but === will not. I understand that the following code will be true:

console.log(true == "1"); 

but when is the code below false?

 console.log(true == "true"); 

Answer 1

If you freely compare a boolean value with a value of another type, the boolean value is forcibly entered into a number.

And when you compare the number and the string, the string is forcibly entered into the number.

Complete rules are explained in the Abstract Equality Comparison Algorithm

The process is as follows:

 true == "true" ─┐ ├─ Number(true) // 1 1 == "true" ─┤ ├─ Number("true") // NaN 1 == NaN ─┤ ├─ // Comparing with `NaN` always produces `false` false ─┘ 

Answer 2

The logical operand is converted to a numerical value, and the strings are converted to a numerical value, since one operand is a number.

The result is 1 == NaN. If either operand is NaN, the equal operator always returns false.