Get Ready For Segue In Swift

Question

I came across an error message:

"UIStoryboardSegue does not have a member named 'identifier'" 

Here is the code causing the error

 if (segue.identifier == "Load View") { // pass data to next view } 

In Obj-C, it works fine as follows:

 if ([segue.identifier isEqualToString:@"Load View"]) { // pass data to next view } 

What am I doing wrong?

Answer 1

This is due to a problem in the template subclass of UITableViewController . It comes with a version of the prepareForSegue method, which would require you to deploy segue.

Replace the current prepareForSegue function with:

 override func prepareForSegue(segue: UIStoryboardSegue!, sender: AnyObject!) { if (segue.identifier == "Load View") { // pass data to next view } } 

This version implicitly expands the parameters, so you should be fine.

Answer 2

Swift 4, Swift 3

 override func prepare(for segue: UIStoryboardSegue, sender: Any?) { if segue.identifier == "MySegueId" { if let nextViewController = segue.destination as? NextViewController { nextViewController.valueOfxyz = "XYZ" //Or pass any values nextViewController.valueOf123 = 123 } } } 

Answer 3

I think the problem is what you should use! split id

I have

 override func prepareForSegue(segue: UIStoryboardSegue?, sender: AnyObject?) { if segue!.identifier == "Details" { let viewController:ViewController = segue!.destinationViewController as ViewController let indexPath = self.tableView.indexPathForSelectedRow() viewController.pinCode = self.exams[indexPath.row] } } 

I understand that without! you just get true or false value

Answer 4

For Swift 2.3, swift3, and swift4:

Create a Segue Performance on didSelectRowAtindexPath

For example:

  self.performSegue(withIdentifier: "uiView", sender: self) 

After that, create the prepareforSegue function to catch the Destination transition and pass the value:

Example:

  override func prepare(for segue: UIStoryboardSegue, sender: Any?) { if segue.identifier == "uiView"{ let destView = segue.destination as! WebViewController let indexpath = self.newsTableView.indexPathForSelectedRow let indexurl = tableDatalist[(indexpath?.row)!].link destView.UrlRec = indexurl //let url = } } 

You need to create a variable called UrlRec in the Destination ViewController

Answer 5

Swift 1.2

  override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject!) { if (segue.identifier == "ShowDeal") { if let viewController: DealLandingViewController = segue.destinationViewController as? DealLandingViewController { viewController.dealEntry = deal } } } 

Answer 6

Get ready for Segue in Swift 4.2 and Swift 5.

  override func prepare(for segue: UIStoryboardSegue, sender: Any?) { if (segue.identifier == "OrderVC") { // pass data to next view let viewController = segue.destination as? MyOrderDetailsVC viewController!.OrderData = self.MyorderArray[selectedIndex] } } 

How to trigger a transition to a specific event (for example, pressing a button, etc.):

 performSegue(withIdentifier: "OrderVC", sender: self) 

Answer 7

This is one of the ways you can use this function when you want to access a variable of another class and change the output based on this variable.

  override func prepare(for segue: UIStoryboardSegue, sender: Any?) { let something = segue.destination as! someViewController something.aVariable = anotherVariable } 

Answer 8

Provided that you are not using the same destination view controller with different identifiers, the code may be shorter than other solutions (and some other answers don't use as! ):

 override func prepare(for segue: NSStoryboardSegue, sender: Any?) { if let myViewController = segue.destinationController as? MyViewController { // Set up the VC } } 

Answer 9

Change the segue id in the right pane in the id section. An icon that matches the string that you used in the conditional expression.

Answer 10

 override func prepareForSegue(segue: UIStoryboardSegue?, sender: AnyObject?) { if(segue!.identifier){ var name = segue!.identifier; if (name.compare("Load View") == 0){ } } } 

You cannot compare id with ==, you have to use compare () method