I have a data URI that I get from javascript and try to save using php. I am using the following code which gives an obviously damaged image file:
$data = $_POST['logoImage']; $uri = substr($data,strpos($data,",")+1); file_put_contents($_POST['logoFilename'], base64_decode($uri)); data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAoAAAAKCAYAAACNMs 9AAAACXBIWXMAAAsTAAALEwEAmpwYAAAAxklEQVQYlYWQMW7CUBBE33yITYUUmwbOkBtEcgUlTa7COXIVV5RUkXKC5AxU EdyZVD4kyKxkwIrr9vd0c7Oih aopinLNsF6Qkg2XW4XJ7LGFsAAcTV6lF5/jLdbALA9XDAXYfthFQVx OrmqKYK88/7rbbMFksALieTnzu9wDYTj6f70PKsp2kwAiSvjXNcvkWpAfNZkzWa/5a9yT7fdoX7rrB7hYh2fXo9HdjPYQZu3MIU8bYIlW20y0RUlXG2Kpv/vfwLxhTaSQwWqwhAAAAAElFTkSuQmCC
The code below is the actual image as a data URI. 'logoImage' is the line above, and $ uri is the line minus' image / jpeg; base64, '.
php file-io image data-uri
GAgnew Jul 18 '11 at 15:33 2011-07-18 15:33
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