Each type of object has a constructor - otherwise how would you build it? - and the destructor - otherwise, how will it be destroyed? They don’t “bother” anyone, because the default implementation is non-ops in the case of POD fields, as if you said:
struct f { f() {} ~f() {} int a, b, c, d; };
However, if you write an empty constructor, the type becomes a non-POD. C ++ 11 resolves this with default:
f() = default; ~f() = default;
The situation is slightly different from copy constructors where implicitly generated is just a convenience that does the “right thing” for POD types:
f(const f& other) : a(other.a), b(other.b), c(other.c), d(other.d) {}
There is no reason to rewrite this yourself. If you want to make the type noncopyable, you can mark the copy constructor as deleted with f(const f&) = delete; or declare it private .
It is also important to note that member functions are not stored in the object as member variables. You can think of a class or struct as two things:
The C ++ object-oriented programming model simply combines these two things in one place.
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