Authenticated sessionFactory object is null

Question

Getting a null pointer exception in the UesrDAO class, because the sessionFactory object is always zero. If this helps, I found out that this happens if the DAO is created manually using the "new", and does not allow spring to process it. I do not do this, I injected UserDAO into the service class, but still get sessionFactory as null.

Any help is appreciated, thanks.

The following is the contents of the relevant files:

hibernate.cfg.xml

<?xml version='1.0' encoding='utf-8'?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd"> <bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"> <property name="location"> <value>/WEB-INF/properties/database.properties</value> </property> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${jdbc.driverClassName}" /> <property name="url" value="${jdbc.url}" /> <property name="username" value="${jdbc.username}" /> <property name="password" value="${jdbc.password}" /> </bean> <bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean"> <property name="dataSource"> <ref bean="dataSource"/> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop> <prop key="hibernate.show_sql">true</prop> </props> </property> <property name="packagesToScan"> <list> <value>org.questionbank.dto</value> </list> </property> </bean> </beans> 

applicationContext.xml

 <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:security="http://www.springframework.org/schema/security" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:mvc="http://www.springframework.org/schema/mvc" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.2.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.2.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.2.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd"> <import resource="hibernate.cfg.xml"/> <mvc:annotation-driven /> <tx:annotation-driven /> <context:annotation-config /> <!-- To scan the components --> <context:component-scan base-package="org.questionbank"/> <bean id = "transactionManager" class = "org.springframework.orm.hibernate4.HibernateTransactionManager"> <property name = "sessionFactory" ref = "sessionFactory" /> </bean> </beans> 

DAO Class:

 public class UserDAO { protected static Logger logger = Logger.getLogger("dao"); @Autowired private SessionFactory sessionFactory; public UserDTO searchDatabase(String username) { logger.debug("Seraching for user in DB"); UserDTO user=new UserDTO(); Query query = sessionFactory.getCurrentSession().createQuery("FROM UserDTO u WHERE u.userName = :userName"); query.setParameter("userName", username); user = (UserDTO) query.uniqueResult(); if(user!=null) return user; logger.error("User does not exist!"); throw new RuntimeException("User does not exist!"); } } 

Class of service:

 @Transactional(readOnly = true) public class CustomUserDetailsService implements UserDetailsService { protected static Logger logger = Logger.getLogger("service"); @Autowired private UserDAO userDAO; public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException, DataAccessException { UserDetails user = null; try { UserDTO dbUser = userDAO.searchDatabase(username); user = new User( dbUser.getUserName(), dbUser.getPassword().toLowerCase(), true, true, true, true, getAuthorities(Integer.parseInt(dbUser.getAccess()))); } catch (Exception e) { logger.error("Error in retrieving user"); e.printStackTrace(); throw new UsernameNotFoundException("Error in retrieving user"); } return user; } 

Answer 1

Your current configuration with <context:annotation-config /> and <context:component-scan base-package="org.questionbank"/> allows the first half of the functionality you need for Spring to correctly recognize and enter your bean.

The other half actually declares the bean as a Spring-installed component.

You can do this in one of two ways. Either declare the bean in applicationContext.xml with the <bean /> (as with your transactionManager ), or use a stereotype annotation (e.g. @Component , @Repository , @Service or @Controller ).

 @Repository public class UserDAO { // ... 

and

 @Service public class CustomUserDetailsService { // ...