Programmatically set image for UIImageView with Xcode 6.1 / Swift

Question

I am trying to install UIImageView programmatically in Xcode 6.1:

@IBOutlet weak var bgImage: UIImageView! var image : UIImage = UIImage(named:"afternoon")! bgImage = UIImageView(image: image) bgImage.frame = CGRect(x: 0, y: 0, width: 100, height: 200) view.addSubview(bgImage) 

But Xcode says "expected announcement" with bgImage = UIImageView(image: image) The image "afternoon" is a PNG, and I understand that PNG does not need to be expanded in Xcode 6.1.

Also tried just bgImage.image = UIImage(named: "afternoon") , but still get:

UPDATE

Ok, I put the code for updating the UIImageView in the viewDidLoad function, but the UIImageView still doesn’t show the image (which exists in the base directory as day UIImageView ):

 @IBOutlet weak var bgImage: UIImageView! @IBOutlet weak var dateLabel: UILabel! @IBOutlet weak var timeLabel: UILabel! override func viewDidLoad() { super.viewDidLoad() // Do any additional setup after loading the view, typically from a nib. updateTime() var timer = NSTimer() let aSelector : Selector = "updateTime" timer = NSTimer.scheduledTimerWithTimeInterval(0.01, target: self, selector: aSelector, userInfo: nil, repeats: true) var image : UIImage = UIImage(named:"afternoon")! bgImage = UIImageView(image: image) } 

Answer 1

Since you have your bgImage assigned and connected as an IBOutlet, there is no need to initialize it as a UIImageView ... instead, all you have to do is set the image property, for example bgImage.image = UIImage(named: "afternoon") . After running this code, the image turned out to be beautiful, because it was already assigned using the outlet.

However, if it was not an output and you did not already have it connected to the UIImageView object in the / xib storyboard file, then you could something like the following ...

 class ViewController: UIViewController { var bgImage: UIImageView? override func viewDidLoad() { super.viewDidLoad() var image: UIImage = UIImage(named: "afternoon")! bgImage = UIImageView(image: image) bgImage!.frame = CGRectMake(0,0,100,200) self.view.addSubview(bgImage!) } } 

Answer 2

In xcode 8, you can directly select an image from the selection window (NEW) ...

• You just need to type - “image”, and you will receive an offer then select “Image Literature” from the list (see attached image) and

• then click on the square, you can see all the images (see the second attached image) that are in your images ... or select another image from there.

• Now touch the square square - (you will see this square box after selecting above)

Answer 3

OK, it works with this (creating a UIImageView programmatically):

 var imageViewObject :UIImageView imageViewObject = UIImageView(frame:CGRectMake(0, 0, 600, 600)) imageViewObject.image = UIImage(named:"afternoon") self.view.addSubview(imageViewObject) self.view.sendSubviewToBack(imageViewObject) 

Answer 4

How about this one;

 myImageView.image=UIImage(named: "image_1") 

where image_1 is in the resource folder as image_1. png .

This worked for me since I am using a switch case to display a slide image.

Answer 5

This code is in the wrong place:

 var image : UIImage = UIImage(named:"afternoon")! bgImage = UIImageView(image: image) bgImage.frame = CGRect(x: 0, y: 0, width: 100, height: 200) view.addSubview(bgImage) 

You must put it inside the function. I recommend moving it inside the viewDidLoad function.

In general, the only code you can add inside a class that is not part of a function is variable declarations:

 @IBOutlet weak var bgImage: UIImageView! 

Answer 6

With quick syntax, this worked for me:

  let leftImageView = UIImageView() leftImageView.image = UIImage(named: "email") let leftView = UIView() leftView.addSubview(leftImageView) leftView.frame = CGRect(x: 0, y: 0, width: 40, height: 40) leftImageView.frame = CGRect(x: 10, y: 10, width: 20, height: 20) userNameTextField.leftViewMode = .always userNameTextField.leftView = leftView 

Answer 7

In Swift 4, if the image returns as zero.

Click on the image on the right side (Utilities) → Check Target Membership

Answer 8

If you want to do it the way you showed in your question, this is the way to make it inline

 class YourClass: UIViewController{ @IBOutlet weak var tableView: UITableView! //other IBOutlets //THIS is how you declare a UIImageView inline let placeholderImage : UIImageView = { let placeholderImage = UIImageView(image: UIImage(named: "nophoto")) placeholderImage.contentMode = .scaleAspectFill return placeholderImage }() var someVariable: String! var someOtherVariable: Int! func someMethod(){ //method code } //and so on } 

Answer 9

You just need to drag the ImageView , create a socket action, bind it and provide the image (Xcode will look in the folder of your assets name you specified (here: "toronto"))

In yourProject/ViewController.swift

 import UIKit class ViewController: UIViewController { @IBOutlet weak var imgView: UIImageView! override func viewDidLoad() { super.viewDidLoad() imgView.image = UIImage(named: "toronto") } }