Radio buttons not marked in jQuery

Question

I have this line of code to load the page:

if ($("input").is(':checked')) { 

and it works fine when the switch is set. However, I want the opposite. Something along the lines

 if ($("input").not(.is(':checked'))) { 

so the my if statement runs when none of the radio blocks are selected. What is the best way to do this?

Answer 1

 if ( ! $("input").is(':checked') ) 

Does not work?

You can also try iterating over the following elements:

 var iz_checked = true; $('input').each(function(){ iz_checked = iz_checked && $(this).is(':checked'); }); if ( ! iz_checked ) 

Answer 2

 if ($("input").is(":not(:checked)")) 

AFAIK, this should work, tested against the latest stable jQuery (1.2.6).

Answer 3

If my firebug profiler is working fine (and I know how to use it), this is:

 $('#communitymode').attr('checked') 

faster than

 $('#communitymode').is('checked') 

You can try this page :)

And then you can use it as

 if($('#communitymode').attr('checked')===true) { // do something } 

Answer 4

 $("input").is(":not(':checked')")) 

This is jquery 1.3, pay attention to the signs and!

Answer 5

 $('input:radio[checked=false]'); 

it will also work

 input:radio:not(:checked) 

or

 :radio:not(:checked) 

Answer 6

check this

 if($("#selector").is(":checked")) { alert('Checked'); } else { alert('Not checked'); } 

You can specify id or class, for example, in the place of the selector

Answer 7

This also works. Shortest working notation seems to be:! !$('#selector:checked')