How to set image from dynamically dynamically to android?

Question

I save my project-related images in a selectable folder. I also save the image names in a string variable and dynamically try to set these images to an image. But the image is not displayed. Please help me with this.

My code is:

int res = getResources().getIdentifier(imagename, "drawable", this.getPackageName()); imageview= (ImageView)findViewById(R.id.imageView); imageview.setImageResource(res); 

In the above code, "imagename" is a string variable that contains the name of the image.

Thank you in advance

Answer 1

Try the following:

 String uri = "@drawable/myresource"; // where myresource (without the extension) is the file int imageResource = getResources().getIdentifier(uri, null, getPackageName()); imageview= (ImageView)findViewById(R.id.imageView); Drawable res = getResources().getDrawable(imageResource); imageView.setImageDrawable(res); 

Answer 2

Here I set the frnd_inactive image from drawable to the image

  imageview= (ImageView)findViewById(R.id.imageView); imageview.setImageDrawable(getResources().getDrawable(R.drawable.frnd_inactive)); 

Answer 3

 imageview= (ImageView)findViewById(R.id.imageView); imageview.setImageResource(R.drawable.mydrawable); 

Answer 4

Try this Dynamic Code

 String fnm = "cat"; // this is image file name String PACKAGE_NAME = getApplicationContext().getPackageName(); int imgId = getResources().getIdentifier(PACKAGE_NAME+":drawable/"+fnm , null, null); System.out.println("IMG ID :: "+imgId); System.out.println("PACKAGE_NAME :: "+PACKAGE_NAME); // Bitmap bitmap = BitmapFactory.decodeResource(getResources(),imgId); your_image_view.setImageBitmap(BitmapFactory.decodeResource(getResources(),imgId)); 

In the above code, you will need the Image-file-Name and Image-View object that you have .

Answer 5

See below code that works for me

 iv.setImageResource(getResources().getIdentifier( "imagename", "drawable", "com.package.application")); 

Answer 6

This works for me (don't use image extension, just name):

 String imagename = "myImage"; int res = getResources().getIdentifier(imagename, "drawable", this.getPackageName()); imageview= (ImageView)findViewById(R.id.imageView); imageview.setImageResource(res); 

Answer 7

Here is the best way it works on every phone today . Most of these answers are deprecated or need API> = 19 or 22. You can use the fragment code or the action code, which depends on what you need.

Fragment

 //setting the bitmap from the drawable folder Bitmap bitmap= BitmapFactory.decodeResource(getActivity().getResources(), R.drawable.my_image); //set the image to the imageView imageView.setImageBitmap(bitmap); 

activity

 //setting the bitmap from the drawable folder Bitmap bitmap= BitmapFactory.decodeResource(MyActivity.this.getResources(), R.drawable.my_image); //set the image to the imageView imageView.setImageBitmap(bitmap); 

Hurrah!

Answer 8

 imageView.setImageResource(R.drawable.picname); 

Answer 9

getDrawable() deprecated, so try

 imageView.setImageResource(R.drawable.fileName) 

Answer 10

First, the name of your image is myimage . So what you need to do is go to Drawable and save the image name myimage .

Now suppose that you only know the name of the image, and you need to access it. Use the snippet below to access it,

what you did right, make sure you save the name of the image that you are going to use inside the encoding.

 public static int getResourceId(Context context, String name, String resourceType) { return context.getResources().getIdentifier(toResourceString(name), resourceType, context.getPackageName()); } private static String toResourceString(String name) { return name.replace("(", "") .replace(")", "") .replace(" ", "_") .replace("-", "_") .replace("'", "") .replace("&", "") .toLowerCase(); } 

In addition to this, you must ensure that there are no empty spaces or case sensitivity.

Answer 11

Starting with API 22, getResources().getDrawable() deprecated (see also Android getResources (). GetDrawable () is deprecated API 22 ). Here is a new way to dynamically set an image resource:

 String resourceId = "@drawable/myResourceName"; // where myResourceName is the name of your resource file, minus the file extension int imageResource = getResources().getIdentifier(resourceId, null, getPackageName()); Drawable drawable = ContextCompat.getDrawable(this, imageResource); // For API 21+, gets a drawable styled for theme of passed Context imageview = (ImageView) findViewById(R.id.imageView); imageview.setImageDrawable(drawable); 

Answer 12

This works great for me.

 final R.drawable drawableResources = new R.drawable(); final Class<R.drawable> c = R.drawable.class; final Field[] fields = c.getDeclaredFields(); for (int i=0; i < fields.length;i++) { resourceId[i] = fields[i].getInt(drawableResources); /* till here you get all the images into the int array resourceId.*/ } imageview= (ImageView)findViewById(R.id.imageView); if(your condition) { imageview.setImageResource(resourceId[any]); } 

Answer 13

getDrawable () is deprecated. now you can use

 imageView.setImageDrawable(ContextCompat.getDrawable(this,R.drawable.msg_status_client_read)) 

Answer 14

 int[] phptr=new int[5]; 

adding image pointer to array

 for(int lv=0;lv<3;lv++) { String id="a"+String.valueOf(lv+1); phptr[lv]= getResources().getIdentifier(id, "drawable", getPackageName()); } for(int loopvariable=0;loopvariable<3;loopvariable++) { et[loopvariable] = findViewById(p[loopvariable]); } for(int lv=0;lv<3;lv++) { et[k].setImageResource(phptr[k]); }