Parsing request string in node.js

Question

In this example, "Hello World":

// Load the http module to create an http server. var http = require('http'); // Configure our HTTP server to respond with Hello World to all requests. var server = http.createServer(function (request, response) { response.writeHead(200, {"Content-Type": "text/plain"}); response.end("Hello World\n"); }); // Listen on port 8000, IP defaults to 127.0.0.1 server.listen(8000); // Put a friendly message on the terminal console.log("Server running at http://127.0.0.1:8000/"); 

How can I get the parameters from the query string?

 http://127.0.0.1:8000/status?name=ryan 

The documentation mentioned:

 node> require('url').parse('/status?name=ryan', true) { href: '/status?name=ryan' , search: '?name=ryan' , query: { name: 'ryan' } , pathname: '/status' } 

But I did not understand how to use it. Can anyone explain?

Thank you in advance

Answer 1

You can use the parse method from the URL module in the request callback.

 var http = require('http'); var url = require('url'); // Configure our HTTP server to respond with Hello World to all requests. var server = http.createServer(function (request, response) { var queryData = url.parse(request.url, true).query; response.writeHead(200, {"Content-Type": "text/plain"}); if (queryData.name) { // user told us their name in the GET request, ex: http://host:8000/?name=Tom response.end('Hello ' + queryData.name + '\n'); } else { response.end("Hello World\n"); } }); // Listen on port 8000, IP defaults to 127.0.0.1 server.listen(8000); 

I suggest you read the documentation for the HTTP module to get an idea of ​​what you get in the createServer . You should also take a look at sites like http://howtonode.org/ and check out the Express framework to get started with Node faster.

Answer 2

There is also a QueryString parse() module :

 var http = require('http'), queryString = require('querystring'); http.createServer(function (oRequest, oResponse) { var oQueryParams; // get query params as object if (oRequest.url.indexOf('?') >= 0) { oQueryParams = queryString.parse(oRequest.url.replace(/^.*\?/, '')); // do stuff console.log(oQueryParams); } oResponse.writeHead(200, {'Content-Type': 'text/plain'}); oResponse.end('Hello world.'); }).listen(1337, '127.0.0.1'); 

Answer 3

node -v v9.10.1

If you try to directly block the log request object, you will get a TypeError error TypeError: Cannot convert object to primitive value

Therefore, I would suggest using JSON.stringify

 const http = require('http'); const url = require('url'); const server = http.createServer((req, res) => { const parsedUrl = url.parse(req.url, true); const path = parsedUrl.pathname, query = parsedUrl.query; const method = req.method; res.end("hello world\n"); console.log('Request received on: ${path} + method: ${method} + query: ${JSON.stringify(query)}'); console.log('query: ', query); }); server.listen(3000, () => console.log("Server running at port 3000")); 

So do curl http://localhost:3000/foo\?fizz\=buzz will return Request received on: /foo + method: GET + query: {"fizz":"buzz"}

Answer 4

 require('url').parse('/status?name=ryan', {parseQueryString: true}).query 

is returning

 { name: 'ryan' } 

ref: https://nodejs.org/api/url.html#url_urlobject_query