Dividing a column into positive and negative values

Question

How do you split a column into two different columns based on criteria, but keep one key? for example

      col1  col2   time       value
0      A     sdf  16:00:00     100
1      B     sdh  17:00:00     -40
2      A     sf   18:00:45     300 
3      D     sfd  20:04:33     -89

I need a new dataframe like this

     time       main_val    sub_val
0   16:00:00     100         NaN
1   17:00:00     NaN         -40
2   18:00:45     300         NaN
3   20:04:33     NaN         -89

Answer 1

You can use mask:

mask = df['value'] < 0
df['main_val'] = df['value'].mask(mask)
df['sub_val'] = df['value'].mask(~mask)
df = df.drop(['col1','col2', 'value'], axis=1)
print (df)
       time  main_val  sub_val
0  16:00:00     100.0      NaN
1  17:00:00       NaN    -40.0
2  18:00:45     300.0      NaN
3  20:04:33       NaN    -89.0

Answer 2

I use pd.get_dummies, maskandmul

n = {True: 'main_val', False: 'sub_val'}
m = pd.get_dummies(df.value > 0).rename(columns=n)
df.drop('value', 1).join(m.mask(m == 0).mul(df.value, 0))

  col1 col2      time  sub_val  main_val
0    A  sdf  16:00:00      NaN     100.0
1    B  sdh  17:00:00    -40.0       NaN
2    A   sf  18:00:45      NaN     300.0
3    D  sfd  20:04:33    -89.0       NaN

---

If you look m.mask(m == 0), it becomes clearer how it works.

   sub_val  main_val
0      NaN       1.0
1      1.0       NaN
2      NaN       1.0
3      1.0       NaN

pd.get_dummies . np.nan. mul, df.value , . join, .

---

numpy

v = df.value.values[:, None]
m = v > 0
n = np.where(np.hstack([m, ~m]), v, np.nan)
c = ['main_val', 'sub_val']
df.drop('value', 1).join(pd.DataFrame(n, df.index, c))

   sub_val  main_val
0      NaN       1.0
1      1.0       NaN
2      NaN       1.0
3      1.0       NaN

Answer 3

This can be done using a pivot table.

df['Val1'] = np.where(df.value >=0,'main_val','sub_val' )

df = pd.pivot_table(df,index='time', values='value',
                columns=['Val1'], aggfunc=np.sum).reset_index()

df = pd.DataFrame(df.values)
df.columns = ['time','main_val','sub_val']