, , A B. , A B . C, , A, B?
Further suppose that the partition of points into sqrt (N) is a hyperbox with points sqrt (N) each. For any pair of hyperboxes, we can calculate in k time the maximum distance between any two points in an infinite number of points contained in them - simply by calculating the distance between their farthest corners. If we already have a candidate better than this, we can drop all pairs of points from these hyperboxes.
source
share