What to do with size_t and std :: size_t?

Question

Just reading:

Does "std :: size_t" make sense in C ++?

I understand that use is ::size_tnot up to standard (although supported by my compiler) when you are #include <cstddef>. I want to conform to the standard, but I do not want to add std::to all mine size_t. So what is the more familiar / popular way to handle this:

• to write using std::size_t;?
• turn on <stddef.h>?
• just rely on compiler support?
• something else?

Answer 1

You must specify it using the use directive.

using std::size_t;

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A) "size_t" AND "stddef.h" language:c++
B) "std::size_t" AND "<cstddef>" language:c++
C) "size_t" AND "<cstddef>" AND NOT "std::size_t" language:c++
D) "size_t" AND "<cstddef>" AND "using namespace std" AND NOT "std::size_t" language:c++
E) "size_t" AND "<cstddef>" AND "using std::size_t" language:c++

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• A) 974 239 ( stddef.h)
• B) 1,230,021 ( cstddef std:: pre)
• C) 469 721 ( cstddef, )
• D) 32 539 (cstddef , " std", !)
• E) 27 080 (, , " std:: size_t" )

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Answer 2

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GitHub "size_t" ++: 24 835 033 .

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